C# 读写XML文件实例代码

C#史上最简单读写xml文件方式，创建控制台应用程序赋值代码，就可以运行，需要改动，请自行调整

using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Xml;

namespace ConsoleApp1
{
  class Program
  {
    public const String xmlPath = "info.xml";

    static void Main(string[] args)
    {

      IDictionary<String, List<String>> infos = new Dictionary<String, List<String>>();

      infos.Add("Evan", new List<string>() { "123", "456" });

      SaveXML(infos);

      ReadXML();
      Console.ReadKey();
    }

    public static void SaveXML(IDictionary<String, List<String>> infos)
    {
      if (infos == null || infos.Count == 0)
      {
        return;
      }

      XmlDocument xmlDoc = new XmlDocument();

      XmlDeclaration dec = xmlDoc.CreateXmlDeclaration("1.0", "utf-8", null);

      xmlDoc.AppendChild(dec);

      XmlElement _infos = xmlDoc.CreateElement("infos");

      foreach (KeyValuePair<String, List<String>> item in infos)
      {
        XmlElement info = xmlDoc.CreateElement("info");

        XmlElement name = xmlDoc.CreateElement("file1");
        name.InnerText = item.Key;

        info.AppendChild(name);

        XmlNode filelist = xmlDoc.CreateElement("filelist");

        info.AppendChild(filelist);

        foreach (String number in item.Value)
        {
          XmlElement filed = xmlDoc.CreateElement("filed");
          filed.InnerText = number;

          filelist.AppendChild(filed);
        }

        _infos.AppendChild(info);
      }

      xmlDoc.AppendChild(_infos);

      xmlDoc.Save(xmlPath);
    }

    public static IDictionary<String, List<String>> ReadXML()
    {
      IDictionary<String, List<String>> infos = new Dictionary<String, List<String>>();

      if (File.Exists(xmlPath))
      {
        XmlDocument xmlDoc = new XmlDocument();

        xmlDoc.Load(xmlPath);

        XmlNode xn = xmlDoc.SelectSingleNode("infos");

        XmlNodeList xnl = xn.ChildNodes;

        foreach (XmlNode xnf in xnl)
        {
          XmlElement xe = (XmlElement)xnf;

          XmlNode nameNode = xe.SelectSingleNode("file1");

          string name = nameNode.InnerText;
          Console.WriteLine(name);
          XmlNode filelist = xe.SelectSingleNode("filelist");

          List<String> list = new List<string>();

          foreach (XmlNode item in filelist.ChildNodes)
          {
            list.Add(item.InnerText);
          }

          infos.Add(name, list);
        }
      }

      return infos;
    }
  }
}

内容扩展：

实例代码

dim domxmldocument as system.xml.xmldocument 
  dim tmppath as string = apptempfilepath 
  dim xmlfile as string = tmppath + "＼testxml.xml" 
 '窗体加载事件 
  private sub testxml_load(byval sender as system.object, byval e as system.eventargs) handles mybase.load 
  '读xml过程测试通过 
  dim domxmldocument as system.xml.xmldocument 
  dim tmppath as string = apptempfilepath 
  dim xmlfile as string = tmppath + "＼testxml.xml" 
  dim reader as system.xml.xmlreader = nothing 
  try 
  reader = new xml.xmltextreader(xmlfile) 
  'reader. 
  while reader.read 
  me.lboxxml.items.add(reader.name + reader.value) 
  end while 
  catch ex as exception 
  msgbox(ex.message) 
  finally 
  if not (reader is nothing) then 
  reader.close() 
  end if 
  end try 
  end sub 
  '载入xml事件 
  private sub btnxmlload_click(byval sender as system.object, byval e as system.eventargs) handles btnxmlload.click 
  'me.lboxxml.items.clear() 
  ''读xml过程测试通过 
  'dim reader as system.xml.xmlreader = nothing 
  'try 
  ' reader = new xml.xmltextreader(xmlfile) 
  ' while reader.read 
  ' me.lboxxml.items.add(reader.name + ":" + reader.value) 
  ' end while 
  'catch ex as exception 
  ' msgbox(ex.message) 
  'finally 
  ' if not (reader is nothing) then 
  ' reader.close() 
  ' end if 
  'end try 
  dim ds as new dataset 
  try 
  '如果直接使用ds做datasource则不会展开datagrid，用dv则能直接显示正确。 
  ds.readxml(xmlfile) 
  dim tb as datatable 
  dim dv as dataview 
  tb = ds.tables(0) 
  dv = new dataview(tb) 
  datagrid1.datasource = dv 
  'datagrid1.datamember = "testxmlmember" 
  'datagrid1.datamember = "employeefname" 
  'dim dxd as new xmldatadocument 
  catch ex as exception 
  msgbox(ex.message.tostring) 
  end try 
  end sub 
  '保存新建xml内容事件 
  private sub btnsavenew_click(byval sender as system.object, byval e as system.eventargs) handles btnsavenew.click 
  dim mytw as new xmltextwriter(tmppath + "＼testxmlwrite.xml", nothing) 
  mytw.writestartdocument() 
  mytw.formatting = formatting.indented 
  mytw.writestartelement("team") 
  mytw.writestartelement("player") 
  mytw.writeattributestring("name", "george zip") 
  mytw.writeattributestring("position", "qb") 
  mytw.writeelementstring("nickname", "zippy") 
  mytw.writeelementstring("jerseynumber", xmlconvert.tostring(7)) 
  mytw.writeendelement() 
  mytw.writeendelement() 
  mytw.writeenddocument() 
  mytw.close() 
  end sub

文件很大的情况下，可以考虑手动实现数据更新适配器，比如手动实现一个xml节点搜索/更新，这样就不用重写整个xml。
如果程序的i/o不是主要问题，还是用实体类整个的写入更新吧，毕竟数据的完整性是第一位的。
如是文章类的，对该目录建一个xml索引文件来存放文章的编号，url等，用xml的attribute作为标记不同字段，内容页面可以用另外的html或xml页面存放，用linq to xml操作数据，效率不是很差，个人观点。当搜索时候只要查询指定文件名xml或文件类型就可以了。

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