要查找不同数量的特定项目,请COUNT()
与GROUP BY子句一起使用。让我们首先创建一个表-
mysql> create table DemoTable1854 ( Name varchar(20) );
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable1854 values('John-Smith'); mysql> insert into DemoTable1854 values('Chris-Brown'); mysql> insert into DemoTable1854 values('Adam-Smith'); mysql> insert into DemoTable1854 values('John-Doe'); mysql> insert into DemoTable1854 values('John-Smith');
使用select语句显示表中的所有记录-
mysql> select * from DemoTable1854;
这将产生以下输出-
+-------------+ | Name | +-------------+ | John-Smith | | Chris-Brown | | Adam-Smith | | John-Doe | | John-Smith | +-------------+ 5 rows in set (0.00 sec)
这是获取列表中特定项目的不同数量的查询-
mysql> select Name,count(Name) from DemoTable1854 where Name like 'John-%' group by Name;
这将产生以下输出-
+------------+-------------+ | Name | count(Name) | +------------+-------------+ | John-Smith | 2 | | John-Doe | 1 | +------------+-------------+ 2 rows in set (0.00 sec)