为此,您可以使用DATE_FORMAT()。让我们首先创建一个表-
mysql> create table DemoTable1820 ( AdmissionDate varchar(20) );
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable1820 values('20/10/2019'); mysql> insert into DemoTable1820 values('19/12/2018'); mysql> insert into DemoTable1820 values('16/04/2017');
使用select语句显示表中的所有记录-
mysql> select * from DemoTable1820;
这将产生以下输出-
+---------------+ | AdmissionDate | +---------------+ | 20/10/2019 | | 19/12/2018 | | 16/04/2017 | +---------------+ 3 rows in set (0.00 sec)
这是查询以减去具有星期几的日期记录并显示星期几名称和记录-
mysql> select DATE_FORMAT(SUBDATE(STR_TO_DATE(AdmissionDate,'%d/%m/%y'), WEEKDAY(STR_TO_DATE(AdmissionDate,'%d/%m/%y'))), '%a %d %b') from DemoTable1820;
这将产生以下输出-
+-------------------------------------------------------------------------------------------------------------------------+ | DATE_FORMAT(SUBDATE(STR_TO_DATE(AdmissionDate,'%d/%m/%y'), WEEKDAY(STR_TO_DATE(AdmissionDate,'%d/%m/%y'))), '%a %d %b') | +-------------------------------------------------------------------------------------------------------------------------+ | Mon 19 Oct | | Mon 14 Dec | | Mon 13 Apr | +-------------------------------------------------------------------------------------------------------------------------+ 3 rows in set, 6 warnings (0.00 sec)