MongoDB中的$unwind从输入文档中解构一个数组字段,以输出每个元素的文档。使用$unwind和aggregate()
来获取计数。让我们创建一个包含文档的集合-
> db.demo478.insertOne( ... { ... ... "Details" : { ... _id:1, ... "Information" : [ ... { ... "Name" : "Chris", ... "Age":21 ... }, ... { ... "Name" : "David", ... "Age":23 ... }, ... { ... ... "Name" : null, ... "Age":22 ... }, ... { ... ... "Name" : null, ... "Age":24 ... } ... ] ... } ... } ... ); { "acknowledged" : true, "insertedId" : ObjectId("5e8204acb0f3fa88e2279092") } > > db.demo478.insertOne( ... { ... ... "Details" : { ... _id:2, ... "Information" : [ ... { ... "Name" : "Bob", ... "Age":21 ... }, ... { ... "Name" : null, ... "Age":20 ... } ... ] ... } ... } ... ); { "acknowledged" : true, "insertedId" : ObjectId("5e8204adb0f3fa88e2279093") }
在find()
方法的帮助下显示集合中的所有文档-
> db.demo478.find();
这将产生以下输出-
{ "_id" : ObjectId("5e8204acb0f3fa88e2279092"), "Details" : { "_id" : 1, "Information" : [ { "Name" : "Chris", "Age" : 21 }, { "Name" : "David", "Age" : 23 }, { "Name" : null, "Age" : 22 }, { "Name" : null, "Age" : 24 } ] } } { "_id" : ObjectId("5e8204adb0f3fa88e2279093"), "Details" : { "_id" : 2, "Information" : [ { "Name" : "Bob", "Age" : 21 }, { "Name" : null, "Age" : 20 } ] } }
以下是实现$unwind以获取计数的查询-
> db.demo478.aggregate([ ... { "$unwind": "$Details.Information" }, ... { ... "$group" : { ... "_id": "$Details.Information.Age", ... "count" : { ... "$sum": { ... "$cond": [ ... { "$gt": [ "$Details.Information.Name", null ] }, ... 1, 0 ... ] ... } ... } ... } ... }, ... { "$sort" : { "count" : -1 } } ... ])
这将产生以下输出-
{ "_id" : 21, "count" : 2 } { "_id" : 23, "count" : 1 } { "_id" : 24, "count" : 0 } { "_id" : 20, "count" : 0 } { "_id" : 22, "count" : 0 }