假设我们有一个名为 points 的数组,其中包含二维平面上的坐标点,它们按 x 值排序,其中 points[i] = (x_i, y_i) 所以 x_i < x_j for all 1 <= i < j <=点数。我们还有另一个值 k。我们必须找到方程 y_i + y_j + |x_i - x_j| 的最大值 其中 |x_i - x_j| <= k 和 1 <= i < j <= 点数。
因此,如果输入类似于 points = [[2,4],[3,1],[6,11],[7,-9]] k = 1,那么输出将为 6,因为前两个点满足条件|xi - xj| <= 1 现在,如果我们计算方程,我们会得到 4 + 1 + |2 - 3| = 6. 第三个和第四个点也满足条件并返回值 11 + -9 + |6 - 7| = 3,所以最大值是 6。
让我们看下面的实现来更好地理解
def solve(points, k): left, right = 0, 1 max_value = float('-inf') while right < len(points): xl, yl = points[left] xr, yr = points[right] diff = abs(xr - xl) if left == right: right += 1 elif diff <= k: m = yl + yr + diff max_value = max(max_value, m) if yl >= yr - diff: right += 1 else: left += 1 else: left += 1 return max_value points = [[2,4],[3,1],[6,11],[7,-9]] k = 1 print(solve(points, k))
[[2,4],[3,1],[6,11],[7,-9]], 1输出结果
6